[geocentrism] Re: acceleration calcs
- From: Allen Daves <allendaves@xxxxxxxxxxxxxx>
- To: geocentrism@xxxxxxxxxxxxx
- Date: Mon, 17 Mar 2008 11:03:37 -0700 (PDT)
Paul, the problem here is not my insitance on somthing that is not ture but
rather your insitance that somthing that is true is false?. For all your words
you still dont get it....starting from 0 to another velocity even if that
velocity is 1 g is always detectable.. inertia is not restricted to "inertial
frames" that is nonesnes and cannot ever be demontrated inertia must take into
account every other gravitaional feild in existance in the universe.......There
is no differnevce in a car at rest then sudenly begins to accelerate at 1 g or
a bomb hangind in the air at rest and then begins to accelerate to 1 g
...somehow you think that becuse the bombs orentaion is verticle makes a
differnece...otherwise you would have to also insist that the car at rest in
the parking lot that suddenly began to aaccelerate to 1 g by force of some
distant planet would not be detected by the occupants or an acceleromter on the
inside!?...............The fact that a
accelerometer would detect the acceleration even with a bomb (even in the
verticle postion..heheh) is a fact questioned only by you and perhaps some
relitivistic assertions...but again my postion is not only verifiable ....it is
a proven fact!
----- Original Message ----
From: Paul Deema <paul_deema@xxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Monday, March 17, 2008 10:50:09 AM
Subject: [geocentrism] Re: acceleration calcs
Allen D
You may recall from history that Galileo did many measurements with masses and
gravity. The outcome can be summarised in the expression -- all objects are
accelerated equally.
Before my bomb drops, the mass extends the upper spring and compresses the
lower spring but the non elastic string retains the bomb fixed in space just as
the is the mass once the extended spring pulls upward with a force equal to the
weight of the mass.
When the string is cut, just as Galileo would correctly predict, the bomb and
the mass on the spring in the bomb, fall at the rate determined by gravity. Now
that the mass is no longer restrained against gravity by the spring (because
the bomb to which it is attached is no longer a fixed object restrained against
gravity but rather a free falling object in the gravity field) then the
extended spring and the compressed spring will return the mass to a central
position thus it will not indicate acceleration.
Now while the bomb, with its internal mass on a spring is indicating zero
acceleration, if we contrive to increase acceleration of the bomb casing with a
rocket, then the mass will be displaced thus indicating acceleration. However,
if instead of using a rocket, we increase the value of gravity, then the bomb
will again accelerate at an increased rate but the acceleration of the mass on
the spring will be similarly increased and it will NOT show acceleration.
Now I admit that, not being a scholar, I have left you a number of
opportunities to exploit and otherwise nit-pick; but I am asking you to show
some maturity, put aside your native intransigence and admit what blind Freddy
can see -- to a first approximation, this is the truth.
There is no way forward until you do.
Paul D
----- Original Message ----
From: Allen Daves <allendaves@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Monday, 17 March, 2008 4:47:23 PM
Subject: [geocentrism] Re: acceleration calcs
Gentleman...Gentelman.......With or without wind resintance, magnetic feilds...
The change itself is always detected.....from any static postion with 0
velocity to any other velocity is always detected.....This is not my opinon
this is a fact.....Ohhhh......... I get it,...... the problem is you absolutly
don't get it.! ....In a free fall any resitance magnetic, wind or otherwise
will affect the craft in the same way......There is no differnce with the wind
then there is by starting from any other non measured "0 velociy" and then
begining an acceleration to a free fall.....!?
----- Original Message ----
From: Paul Deema <paul_deema@xxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Monday, March 17, 2008 9:37:24 AM
Subject: [geocentrism] Re: acceleration calcs
Philip M
Yes Philip, I understand that, but somewhere I defined resistance as zero thus
no wind. In my illustration, the left half shows a bomb/mass/spring suspended
from a sky-hook against the gravity of, say Earth, velocity is zero, and the
universe consists of just these two bodies. The right half differs only in that
the string is broken and the bomb etc falls in a straight line at 9.8 m/s^2.
I took the view that it is reasonable to assume for the sake of argument that
only that which is shown is relevant. OK -- I should have indicated the Earth.
But complications such as magnetic fields, tornadoes, passing comets,
malevolent spirits etc can be added once the basic principle of what happens to
the mass and the springs when the string breaks have been settled. Sadly Allen
still doesn't get it.
Paul D
----- Original Message ----
From: philip madsen <pma15027@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Sunday, 16 March, 2008 10:46:25 PM
Subject: [geocentrism] Re: acceleration calcs
HOwever even then any and all changes to that free fall can and will be
detected even by a mass on a spring......
[PD1] Rubbish. The mass is being accelerated at the same rate as the bomb
casing.
Careeeful Paul.. If a body is in free fall (accelerating in other words,) and
a side wind or an up draft or a magnetic electric force field is met, the
spring will notice the change in speed due to these extraneous effects..
However I agree with you, any change of gravity to a falling body caused by the
orbit of the sun, ie either to the sun or away,from it would not register on
the sprung mass because all elements would feel the change simultaneously..
Allen is on Methodone with this one..
"....just as in the gravitational explinations of planitary bulges"
Philip.
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