[visionegg] Re: falling out of a go() loop which is set torun_forever so that a second go() loop can be allowed to run
- From: Mark Tovey <getmark@xxxxxxxxxxxx>
- To: "visionegg@xxxxxxxxxxxxx" <visionegg@xxxxxxxxxxxxx>
- Date: Fri, 25 Jul 2003 13:00:15 -0400
Hi Andrew,
If you have a quick answer to the following, that would be great (it looks
like a lot of text, but it's a simple question). I've got access to the
magnet room this afternoon, and I'd love to be able to test this.
The basic question is: do I need to reset or delete something if I want do
do:
button_down.set_presentation_instance(p)
p.go()
a second time?
--
In detail:
This works great -- I'm wondering if there's something I need to reset if I
want to run the same presentation again, as in:
button_down.set_presentation_instance(p)
p.go()
button_down.set_presentation_instance(q)
q.go()
button_down.set_presentation_instance(p)
p.go() # this is where the error happens
# as you can see we're running p a second time here
When I try this right now, I get:
Traceback (most recent call last):
File "/Users/mark/VisionEgg/myscripts/runprotocol9.py", line 228, in ?
a.go() # this is where the error happens
File
"/Library/Frameworks/Python.framework/Versions/2.3/lib/python2.3/site-packag
es/VisionEgg/Core.py", line 1354, in go
real_time_since_go = real_time_now - self._real_time_go_start
UnboundLocalError: local variable 'real_time_now' referenced before
assignment
warning: use func(*args, **kwargs) instead of apply(func, args, kwargs)
(I'm using a's and b's in the test programme, but it's the same thing).
Thanks so much!
Mark
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