Dear sir, Whenever we analyzed the inductance of a circuit, we have to consider the loop. Whatever mutual inductance or self-inductance were mentioned, we all need to calculate the area of the loop that was constructed by the forward signal line and the back power plane. That was easy to be comprehended, in terms of the concept of induction, we had to understand that the change of flux led to the loop current. And in this situation, the inductance distributed in the loop nearly uniformly. But most time, we extracted the lead inductance out of the integrated value of the loop, and considered it separately. It seemed that the lead had a inherent inductance which wasn't related to the area of the loop. But I couldn't comprehended how a straight wire, other than loop, could possess the inductance. No area No flux. Thanks a lot. -- BEST WISHES Joey.zhao ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List FAQ wiki page is located at: http://si-list.org/wiki/wiki.pl?Si-List_FAQ List technical documents are available at: http://www.si-list.org List archives are viewable at: //www.freelists.org/archives/si-list or at our remote archives: http://groups.yahoo.com/group/si-list/messages Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu