[SI-LIST] Re: capacitors and bandwidth
- From: Roy M <roymesi@xxxxxxxxx>
- To: narasimha rao <narasimharaopatil@xxxxxxxxx>
- Date: Fri, 4 Feb 2011 20:59:45 +0200
thank you all very much!
got it now...
On Fri, Feb 4, 2011 at 1:05 PM, narasimha rao
<narasimharaopatil@xxxxxxxxx>wrote:
>
> Hi,
> To have a still clear picture on this:-
> Basic capacitance formulaC = Q/V, but Q = IT
> Finally, C = IT/V, since time T is directly proportional to capacitance, by
> adding capacitors it will increase in the time (Tr or Tf) and hence fall in
> the BW.
> Regards,Simha
>
>
>
> --- On Fri, 2/4/11, Shiva T <shivartr@xxxxxxxxx> wrote:
>
> From: Shiva T <shivartr@xxxxxxxxx>
> Subject: [SI-LIST] Re: capacitors and bandwidth
> To: si-list@xxxxxxxxxxxxx
> Date: Friday, February 4, 2011, 11:39 AM
>
>
> Hi,
>
>
> Eric's formula is BW = 0.35/tr or tf. Capacitance of the transmission path
> will
> increase the rise time. Hence if you put those no's in the formula you will
> get
> reduced BW if rise time
> increases.
>
> Regards
> Shiva
>
>
>
>
>
>
> ________________________________
> From: Roy M <roymesi@xxxxxxxxx>
> To: si-list@xxxxxxxxxxxxx
> Sent: Fri, 4 February, 2011 3:12:55 AM
> Subject: [SI-LIST] Re: capacitors and bandwidth
>
> Got it!
> excep Michael... didn't quite understand your example.
> If C is bigger, then I/C is smaller, so dV/dT is smaller, hence...?
> Can you repeat that?
> Roy
>
>
> On Thu, Feb 3, 2011 at 10:38 PM, Roy M <roymesi@xxxxxxxxx> wrote:
>
> > Hi,
> > can anyone explain to me why do capacitors lower the bandwidth?
> > I know it is rather basic question, so I'll happy to be answered a
> thorugh
> >
> solution...
> > Thank you!
> > Roy
> >
>
>
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> Hi,
>
>
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