Hello all, I have a differential driver terminated by 100-ohm at the far end. This is a differential termination between two lines A and B. Termination resistance is matching with the differential characteristic impedance of the trance. Initially signal value on A is 300mV and signal value on B is 600mV. This time common mode voltage is 450mV. Now A is rising from 300mV to 600mV with rise time of 1ns. B falls from 600mV to 300mV with 1ns fall time but skew between A and B is 500ps, means B starts falling 500ps after A starts rising. For the 500ps time A reaches from 300mV to 450mV. During this period there will be change in common mode values of 150mV. I have seen observed that this 150mV rise of A (B remains constant), will cause 75mV reflection on A and 75mV rising of signal at B. I am not able to explain this effect that why the half of delta Vos (change in common mode) is going to B and half is reflected back to the source on trace A. Thanks in advance, Sekhar --------------------------------- Here's a new way to find what you're looking for - Yahoo! Answers Send FREE SMS to your friend's mobile from Yahoo! Messenger Version 8. Get it NOW ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List FAQ wiki page is located at: http://si-list.org/wiki/wiki.pl?Si-List_FAQ List technical documents are available at: http://www.si-list.org List archives are viewable at: //www.freelists.org/archives/si-list or at our remote archives: http://groups.yahoo.com/group/si-list/messages Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu