[SI-LIST] Re: Ground bounce (was VOH datasheet question)
- From: "Andrew Ingraham" <a.ingraham@xxxxxxxx>
- To: <si-list@xxxxxxxxxxxxx>
- Date: Tue, 14 Mar 2006 10:04:59 -0500
> Is the turn-on time for a driver slow rather than instantaneous?
Yes. Drivers don't turn on instantaneously. It's a combination of on-die
and package effects. If you measure turn-on time or slew rate with a
resistive load, you don't get zero or infinity.
Increasing the load capacitance increases the area of the current pulse;
that's all you can say for sure. Some of it is by lengthening the pulse's
width, but also the amplitude may be somewhat larger because it doesn't
instantaneously go to the short-circuit value. In any event, over a range
of typical load capacitances, there is also interaction between the pulse
duration and package impedances, such that the pulsewidth also figures into
the amount of ground bounce you get (if the load capacitance is not so large
that the width greatly exceeds the package time constants).
Regards,
Andy
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