Hi all,
First, Tom, disregard my question about the connector and cable. They fit
eventually. One suggestion for your layout guide: say which side of the board,
identified by grooves or protrusions, is which power. As I understand it, the
side with the protrusions is the 3.3V side?
I now have the board, connector, cable, and Pi all wired up as I understand the
layout to be. Hopefully, I have it right. I also have a button, which has four
wires on it. My question is about as basic as it gets: how do I get the Pi to
detect this button? Not the code--code I can deal with--but the board. What do
the four leads do? How do I get from a lead to the GPIO pins on the connector?
Here's my guess, and people can tell me how horribly wrong I am.
The button has four connectors, two on each side. One pair is for ground, one
for power. I assume each pair has one ground and one power, with each set of
ground/power wires across from each other. That is, if the button's wires were
named the same as the Pi's pins, 1 and 2 would be power, while 3 and 4 would be
ground.
If I want the ground on pins 1 and 3, and the power on 2 and 4, I place the
button anywhere on the board, straddling the central line where there are no
holes. I then take four male-to-male wires, and connect the rows of holes. A
wire goes from pin 1 to the corresponding row, where the wire of the button is,
and so on, connecting each pin to the row of the button's wire.
Is this at all correct? The tutorials I've found online so far have image
instructions, or use LEDs in the circuit. I don't have anyone handy who can
identify the resistors for me, so I don't want to do anything that needs a
resistor just yet. I figure I can't go wrong with a button, though, so long as
I feed power from the 3.3V side. Oh, that leads to one other question: to
connect power, I run male-to-male wires from any pin on the power column I want
(column A in my case) to the power pin, then do the same for B to the ground
pin. Right?
This is starting to make sense in my head, but I want to make sure I'm
picturing all of it correctly before I get too far, try something, and fry $35
of hardware. Thanks in advance for the clarifications and corrections I know
I'll need.
--
Alex Hall
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