[nanomsg] Re: why memcpy data to be sent?
- From: Martin Sustrik <sustrik@xxxxxxxxxx>
- To: nanomsg@xxxxxxxxxxxxx
- Date: Mon, 27 Oct 2014 09:40:51 +0100
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Hi Steve,
> Someone asked this in the #nanomsg channel: why is data to be sent
> copied first?
>
> https://github.com/nanomsg/nanomsg/blob/master/src/core/global.c#L739-L747
There's
>
no guarantee that the supplied scatter array will not be
deallocated by the user while still being used. Therefore nanomsg
makes its own private copy where it can control its lifetime.
Martin
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