[mso] Re: REVISION! SQL in Access :VSMail mx1
- From: "Jim Pettit" <j_e_pettit@xxxxxxxxxxx>
- To: <mso@xxxxxxxxxxxxx>
- Date: Mon, 7 Mar 2005 06:30:41 -0800
Glenda--
In the post I sent a few minutes ago, for things to work properly, the
subquery 'sqryCADDR' in step 1 should read:
SELECT personID, Max(caddrID) AS MaxOfcaddrID FROM CADDR GROUP BY personID,
caddrType HAVING caddrType="email"
My apologies...
--Jim
-----Original Message-----
From: mso-bounce@xxxxxxxxxxxxx [mailto:mso-bounce@xxxxxxxxxxxxx] On Behalf
Of Jim Pettit
Sent: Monday, March 07, 2005 6:21 AM
To: mso@xxxxxxxxxxxxx
Subject: [mso] Re: SQL in Access :VSMail mx1
Glenda--
In this situation -- as in most others -- there is more than one way to
arrive at a solution. Since I can't cover them all, I'll tell you what I
would do:
1) Create and save a subquery which we'll call sqryCADDR, using the
following SQL:
SELECT personID, Max(caddrID) FROM CADDR GROUP BY personID,
caddrType HAVING caddrType="email"
2) Create and save a main query (calling it whatever you want) using the
following SQL:
SELECT sqryCADDR.personID, caddrNmbr FROM sqryCADDR INNER JOIN CADDR
ON sqryCADDR.MaxOfcaddrID = CADDR.caddrID
Running that second query will return the name and email address with the
highest caddrID for each person with an email address. To use it in a form
or report, just do your normal Access magic.
Hope this helps.
--Jim
-----Original Message-----
From: mso-bounce@xxxxxxxxxxxxx [mailto:mso-bounce@xxxxxxxxxxxxx] On Behalf
Of Glenda Wells
Sent: Monday, March 07, 2005 5:45 AM
To: Glenda Wells; mso@xxxxxxxxxxxxx
Subject: [mso] Re: SQL in Access :VSMail mx1
I'm still not getting quite what I want. The result from the SQL is the
one record with the max caddrID.=20
What I'm supposed to get is the caddrNmbr with the max caddrID per
personID where the caddrType is email. =20
I've tried many combinations but haven't been able to make any further
headway.
I'm t-h-i-i-s close but not seeing it.
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