Ned, Yes, of all the pairs of numbers whose sum is 23, the pair having the largest product is {11.5,11.5}. --Nelson ----- Original Message ----- From: Ned Granic To: maths@xxxxxxxxxxxxx Sent: Wednesday, November 29, 2006 5:50 AM Subject: [maths] Re: more of calculus Are we still going on? Is 11.5 the max two numbers (11.5*11.5)whose sum is 23? I think so, just checking. What about previous problems? Many thanks in advance! Desp. Ned ----- Original Message ----- From: Nelson Blachman To: maths@xxxxxxxxxxxxx Sent: Tuesday, November 28, 2006 3:09 AM Subject: [maths] Re: more of calculus Ned, While I was showering just now it occurred to me that something more might be wanted from you in response to problems 1 & 2. I'm unfamiliar with the term "critical numbers," but I'd like to think you're expected to say that in problem 1 f(x) has a local maximum at (-1, 1), a local minimum at (1/3, -5/27), and a point of inflexion half way between at (-1/3, 11/27). In problem 2 there's a point of inflexion at (-1/3, -7/27). --Nelson ---- Original Message ----- From: Ned Granic To: maths@xxxxxxxxxxxxx Sent: Monday, November 27, 2006 5:14 PM Subject: [maths] more of calculus Hi all, Hope you're doing good, good people. I have a list of questions that are marked as even problems in my homework which I doubt the results of, so I'll post the problems and the so-called solutions I kinda found, and if somebody cares to verify if they are accidentally the right ones. Find the critical numbers of the function: 1. q: f(x) = x^3 + x^2 -x. a: 1/3, -1. 2. q: f(x) = x^3 + x^2 + x. a: Not found in R; the imaginary solution I found is (-1+i*sqrt(2))/3. (we don't do imaginary solutions, that was my only escape). Find the absolute maximum and minimum of f on the given interval: 3. q: f(x) = x^3 - 3x + 1, [0,3]. a: abs max is f(0) = 1, f(3) = 1; abs min is f(1) = -1. 4. q: f(x) = x^3 - 6x^2 + 9x + 2, [-1,4]. a: abs min is f(-1) = -14; abs max is f(1) = 6, f(4) = 6. Verify that the function satisfies the 3 hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of that theorem. 5. q: f(x) = x^3 - 3x^2 + 2x + 5, [0,2]. a: Well, the function is a polynomial, therefore continuous and differentiable, and c values are 1 +or- 1/sqrt(3). Verify that the function satisfies the hypothesis of the Mean Value Theorem on the given interval. Then find all numbers c that satisfy the conclusion of the theorem. 6. q: f(x) = x^3 + x - 1, [0,2]. a: c = 7/6; -7/7 is not in the domain of f. 7. f(x) = x/(x+2), [1,4]. a: the c number I've got is (-4+-2*sqrt(3))/2 = (-2+sqrt(3)). <cough, cough> Enough for now, more to come. Sttay tune! And, of course, many thanks in advance! Ned