Re: how to send lua table to c/c++ by luajit.ffi ?
- From: Ryan Gonzalez <rymg19@xxxxxxxxx>
- To: luajit@xxxxxxxxxxxxx
- Date: Tue, 26 Nov 2013 21:06:13 -0600
I think you need this:
ffi.cdef[[
typedef struct { char* a, b, c; } mystruct;
]]
mystruct = ffi.new("mystruct[?]", 3)
mystruct[0] = "a";
mystruct[1] = "b";
mystruct[2] = "c";
Note that I quickly hacked this together, and it is UNTESTED!!!
On Tue, Nov 26, 2013 at 8:58 PM, cosnis zhang <cosnis@xxxxxxxxx> wrote:
> ok..
>
> now, i have a dynamic length lua table… may i convert to FFI structs?
>
> like this
>
> local var = {“a”, “b”, “c"}
> local var1 = {“a”, “b”, “c"}
> local var2 = {“a”, “b”, “c”}
>
> // how to convert to FFI structs.
>
> ffi.C.call(var)
> ffi.C.call(var1)
> ffi.C.call(var2)
>
> --
> cosnis zhang
>
> On 2013年11月27日 at 上午10:50:01, Coda Highland
> (chighland@xxxxxxxxx<//chighland@xxxxxxxxx>)
> wrote:
>
> On Tue, Nov 26, 2013 at 6:38 PM, cosnis zhang <cosnis@xxxxxxxxx> wrote:
> > like the subject, i want send a lua table like {“a”,”b”,”c”} to c/c++
> >
> > and how to read that value by c/c++?
> >
> > and how to get that count by c/c++?
>
> The short answer to your question is "you can't." Lua tables are
> purely Lua constructs and can't be sent to C via the FFI. You can use
> FFI structs to assemble data structures that you can send to C
> functions through the FFI, but if you need more generic table
> manipulation you should simply write the code as Lua code.
>
> Also note that you shouldn't access the Lua state from within a
> function called by the FFI. This is unsupported and can cause crashes.
>
> /s/ Adam
>
>
--
Ryan
When your hammer is C++, everything begins to look like a thumb.
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