Re: ffi can't call function in my executable
- From: GrrrWaaa <grrrwaaa@xxxxxxxxx>
- To: luajit@xxxxxxxxxxxxx
- Date: Sat, 2 Jun 2012 12:38:17 -0700
On Jun 2, 2012, at 11:18 AM, Dan Eloff wrote:
> I declared in lua.cpp:
>
> extern "C" int foo(int bar)
> {
> return bar *en in lua bar;
Not sure what that means?
> }
>
> Then in lua:
>
> local ffi = require("ffi")
> ffi.cdef[[
> int foo(int bar);
> ]]
> local barreturn = lib.foo(5)
Replace above line with:
local barreturn = ffi.C.foo(5)
> io.write(barreturn)
> io.write('\n')
>
> And I load and execute this via luaL_dofile in main.cpp
>
> Which produces the error: "undefined symbol: foo"
>
> I added -rdynamic to gcc flags and running "nm -g mybinary | grep foo" I get:
>
> 00000000004089fc T foo
>
> I'm running on linux with latest "stable" luajit 2 and gcc++ 4.7
>
> Cheers,
> Dan
>
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