[geocentrism] Re: poundal
- From: "philip madsen" <pma15027@xxxxxxxxxxxxxx>
- To: "geocentrism list" <geocentrism@xxxxxxxxxxxxx>
- Date: Thu, 29 Mar 2007 20:44:50 +1000
Neville. said Isn't it a lb-wt (pound-weight)?
You are correct. I confused the poundal as the unit of Mass.. So wrong.
On checking my 1918, revised 1948 Duncan & Starling, I rediscovered that the
unit of mass was pound avoirdupois and was the quantity of matter contained in
a standard piece of platinum preserved in London.
How could I make such an error .. I'm hiding under the table in shame...
Here is what D & S states.
For many practical purposes the weight of the unit of mass is employed as the
unit of force, but this is not strictly scientific. the units were gram weight
, and pound weight lb.wt. as you showed.
The Absolute unit of force and thus weight is the poundal . Which is the force
required to accelerate one lb.wt. one ft.per second.
Thanks for giving me the incentive to lift ye old heavy and worn book down from
the shelf for a refresher course.. You can guess I am antagonistic to using
persons names for units.. Even though now I am forced to use Hz instead of
cycles per second.. Its disgusting. .
Philip.
----- Original Message -----
From: Dr. Neville Jones
To: geocentrism@xxxxxxxxxxxxx
Sent: Thursday, March 29, 2007 8:53 AM
Subject: [geocentrism] Re: Pro-HC physical phenomenon?
Philip,
Isn't it a lb-wt (pound-weight)?
1 lb-wt = 4.5 N is a much closer approximation (Humphrey and Topping,
Intermediate Mechanics, 2nd ed., 1964).
Neville.
philip madsen <pma15027@xxxxxxxxxxxxxx> wrote:
a.. 0.0577 N at the parking orbit altitude under my formula. = a quarter
of an ounce
Thanks Neville, so a newton, (before my time) is equal to 4.3 oz.
handy to remember 1 lb is 3.7 newtons.
Philip.
----- Original Message -----
From: Dr. Neville Jones
To: geocentrism@xxxxxxxxxxxxx
Sent: Wednesday, March 28, 2007 10:18 AM
Subject: [geocentrism] Re: Pro-HC physical phenomenon?
The figures are as follows:
A satellite of mass 300 kg will weigh
a.. 2,942 N at mean sea level
b.. 66 N at the parking orbit altitude under Newton's formula
c.. 0.0577 N at the parking orbit altitude under my formula.
To put this into perspective, the force pulling the satellite back down
under my formula is equivalent to the force you have to exert to lift a quarter
of an ounce weight off your kitchen scales.
Not much, but certainly not zero.
Neville.
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