Mark Lane wrote:
I was a math major in a former life 10+ years. 1/2(e^x + e^-x) = 4 e^x + e^-x = 8 (e^x)^2 + 1 = 8e^x Let y = e^x such that x = ln(y). y^2 + 1 = 8y y^2 - 8y + 1 = 0 Use quadratic formula, which is x = (-b +- sqrt(b^2 - 4ac))/2a, to solve fory in previous equation. Then x = ln(y)
Pretty, but pure handwaving, you still didn't provide a value for x. -- Chris Berry chris_berry@xxxxxxxxxxxxxxxxx Information Advisory Manager JM Associates"If we don't believe in freedom of expression for people we despise, we don't believe in it at all." --Noam Chomsky
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