[windows2000] Re: OT - Math Question
- From: "Mark Lane" <marklanemail@xxxxxxxxx>
- To: <windows2000@xxxxxxxxxxxxx>
- Date: Wed, 29 Nov 2006 13:10:47 -0600
I was a math major in a former life 10+ years.
1/2(e^x + e^-x) = 4
e^x + e^-x = 8
(e^x)^2 + 1 = 8e^x
Let y = e^x such that x = ln(y).
y^2 + 1 = 8y
y^2 - 8y + 1 = 0
Use quadratic formula, which is x = (-b +- sqrt(b^2 - 4ac))/2a, to solve for
y in previous equation.
Then x = ln(y)
-----Original Message-----
From: windows2000-bounce@xxxxxxxxxxxxx
[mailto:windows2000-bounce@xxxxxxxxxxxxx] On Behalf Of Ron Leach
Sent: Wednesday, November 29, 2006 9:24 AM
To: windows2000@xxxxxxxxxxxxx
Subject: [windows2000] Re: OT - Math Question
Only 13 years?!? Try 22 years ;-).
I'm thinking that this might be a start...
1/2(e^x + e^-x) =4
ln (e^x + e^-x)^1/2 = ln 4
ln sqrt (e^x + e^-x) = ln 4
but now where to go...
-----Original Message-----
From: windows2000-bounce@xxxxxxxxxxxxx
[mailto:windows2000-bounce@xxxxxxxxxxxxx] On Behalf Of Costanzo, Ray
Sent: Wednesday, November 29, 2006 9:51 AM
To: windows2000@xxxxxxxxxxxxx
Subject: [windows2000] Re: OT - Math Question
There is not a chance in hell I could ever do this. It's depressing.
Take me back to high school and I think I could do it. Now, 13 years
later, I don't have a clue where to begin. I briefly discussed it with
my brother who said:
<quote>
I don't have time to look at it right now, but my first thought would be
to use the natural log function to pull x out of the exponent.
Example:
e^x = 4
ln(e^x) = ln(4)
x(ln(e)) = ln(4)
x = ln(4)
Your equation may not be so easy, because you'll have ln(e^x + e^-x), so
you can't just move the x out of the exponent.
</quote>
Ray at work
-----Original Message-----
From: Ron Leach
It's been a long while in doing the math problems, so please pardon the
OT.
I was wondering if anyone would be able to help with the following math
problem (a little break from the normal stuff :-))
1/2(e^x + e^-x) = 4, solve for x.
Thanks!
Ron
PS Maybe Jim has a math list? ;-)
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