[windows2000] Re: Multiple arguments in a batch
- From: "Ray at home" <listray@xxxxxxxxxx>
- To: <windows2000@xxxxxxxxxxxxx>
- Date: Mon, 9 Sep 2002 23:11:02 -0400
So, what if 100 dates are passed? I was hoping that there was a
"%RestOfTheDamnArguments" but if not, I'll make do!
Thanks,
Ray at home
>-----Original Message-----
>From: windows2000-bounce@xxxxxxxxxxxxx
>[mailto:windows2000-bounce@xxxxxxxxxxxxx] On Behalf Of Sullivan, Glenn
>
>
>
>Set Dates=%4 %5 %6
>
>Have fun,
>
>Glenn Sullivan, MCSE+I MCDBA
>David Clark Company Inc.
>
>-----Original Message-----
>From: Costanzo, Ray [mailto:rcostanzo@xxxxxxxxxxx]
>Subject: [windows2000] Multiple arguments in a batch
>
>
>
>Hi list,
>
>I'm writing a batch file that will expect some arguments. The
>number of
>arguments can vary, however. Like, someone may enter any of
>these three
>things, for example:
>
>file.bat Arg1 Username Password Date1 Date2 Date3 Date4
>file.bat Arg1 Username Password Date1
>file.bat Arg1 Username Password
>
>
>
>What I want to do would essentially be:
>Set Arg1=%1
>Set User=%2
>Set Pass=%3
>Set Dates=%TheRest
>
>Does anyone know how I can get the rest? I know I can use %*
>for everything
>or %[number] for a specific argument, but is there a way to grab all
>arguments beyond #3 and stick them in one variable?
>
>Thanks,
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