[SI-LIST] Re: question about caculation the emitter follower output quiescent power
- From: "Andrew Ingraham" <a.ingraham@xxxxxxxx>
- To: <si-list@xxxxxxxxxxxxx>
- Date: Tue, 26 Oct 2004 09:27:14 -0400
> why the emitter follower output quiescent power is
> P={(Vcc-Vh)(Vh-Vt)+(Vcc-Vl)(Vl-Vt)}/(2R).
It is nothing but basic circuit theory, and a little algebra.
When the output is high, P = V * I = (Vcc-Vh) * (Vh-Vt)/R.
When the output is low, P = (Vcc-Vl) * (Vl-Vt)/R.
Average them (i.e., 50% duty cycle) , and you get your formula.
Regards,
Andy
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