[SI-LIST] question about caculation the emitter follower output quiescent power

  • From: 朝辉 彭 <sdupzh@xxxxxxxxxxxx>
  • To: si-list@xxxxxxxxxxxxx
  • Date: Tue, 26 Oct 2004 18:00:52 +0800 (CST)

hello everyone,

i am learning Howard's <the high speed digital design>. there is a question,in 
the chapter 2 and page 51, why the emitter follower output quiescent power is
         P={(Vcc-Vh)(Vh-Vt)+(Vcc-Vl)(Vl-Vt)}/(2R).

thanks.

sdupzh





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