[SI-LIST] Re: Rise time bandwidth relation
- From: jaudet@xxxxxxxxxx
- To: rohitsharma@xxxxxxxxxxxxx
- Date: Mon, 7 May 2007 11:21:55 -0400
Based on simple RC circuit... Vo=V*(1-e^(t/RC))
So apply it for 10% and 90% ( risetime )
Vo at 0.1= 0.1*V = 0.1*(1-e^(t at 0.1/(RC))
Vo at 0.9= 0.9*V = 0.9*(1-e^(t at 0.9/(RC))
tr= t at 0.9 - t at 0.1..... and by manipulation on previous equations
you will find tr = 2.2RC
fc= 1/ (2piRC)....
so fc = 0.35/tr
Jean Audet
Electrical Analysis
STG / World Wide Packaging & Test
Organic and Ceramic Packages
IBM Bromont
Tel: 450-534-6317, tie line: 552-6317
E-mail: jaudet@xxxxxxxxxx
Rohit Sharma <rohitsharma@xxxxxxxxxxxxx>
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2007-05-07 11:00
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[SI-LIST] Re: Rise time bandwidth relation
Hi All,
Can somebody help me in understanding the derivation of the following
formula for digital signals:-
Bandwidth = 0.35/Rise time.
Regards,
Rohit
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