[SI-LIST] Re: Open Termination

  • From: "Ahmed El-Sanhoury" <rd-ahsanh@xxxxxxxxxxxxxx>
  • To: <si-list@xxxxxxxxxxxxx>, <si_monkey2@xxxxxxxxx>
  • Date: Wed, 15 Sep 2004 11:35:06 +0300

si_monkey2

I'm afraid that there is misunderstanding point, so i will try to =
declare it:

1- When saying "open termination offers infinite impedance" means Load =
Impedance ZL=3D infinite impedance.=20
2- According to that the input impedance of transmission line Zin equals =
directly the characteristic impedance            Zo.
3- If the transmission line media is air, the Zo =3D 120pi =3D 120x3.14 =
=3D 377ohm.
4- so in this case Zin equals also 377 ohm.

According the above i can modify your statement "Open end line is =
exposed to air has about 377 ohms"
to " Open end line which go through the air has about 377 ohm".

Thanks
Senior Eng A.Sanhoury
IEP  R&D    Bahgat Group
www.bahgat.com
> ----------
> From:         si-list-bounce@xxxxxxxxxxxxx[SMTP:si-list-bounce@xxxxxxxxxxxxx] 
> =
on behalf of Sitar Moniker[SMTP:si_monkey2@xxxxxxxxx]
> Reply To:     si_monkey2@xxxxxxxxx
> Sent:         Wednesday, September 15, 2004 12:48 AM
> To:   si-list@xxxxxxxxxxxxx
> Subject:      [SI-LIST] Open Termination
>=20
> In SI and HSDD books, they assume that open termination offers =
infinite impedance. My understanding is open end line is exposed to air =
which has about 377 ohms.=20
> =20
> 1) How do you get infinite impedance for unterminated line?=20
> =20
> 2) Is there any intuitive way to show that voltage at the open end =
doubles- other than using math: ref. coeft. =3D +1?
> =20
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