Hello all, My question is regarding to TIA/EIA-644-A standard on LVDS.In this standard it is specified that the maximum transistion time for the output signal is 0.3tui. Where tui is the unit interval of output waveform. If I know the 20% to 80% rise time of the output wave of LVDS driver I can calculate its maximum frequency of operation (f=0.3/2*tr), by applying the condition tr=0.3tui.Is this approach for calculating maximum operating frequency is justified? If yes, my second question follows: Rise time tr specified here is the 20% to 80% of Vss, where Vss=2*Vt. Vt is the output differential swing. This Vt may be anything from 250mV to 450mV. Suppose in my case this Vt comes 300mV, then Vss will be 2*300=600mV. But the minimum Vss for LVDS driver is 2*250=500mV. Now for calculating maximum operating frequency, should I take tr equal to 20% to 80% of the total Vss swing of 600mV or should I consider only 500mV swing of Vss, means tr equal to 20% to 80% of the 500mV portion of Vss. If I say that I should take only 500mV portion into consideration, because I am going to calculate maximum operating frequency, am I wrong? Why? Thanks in advance, Thanks and Regards, Sunil C Kasanyal ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List archives are viewable at: //www.freelists.org/archives/si-list or at our remote archives: http://groups.yahoo.com/group/si-list/messages Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu