RE: question about some php code
- From: Ilian Andreev <ilian_andreev@xxxxxx>
- To: programmingblind@xxxxxxxxxxxxx
- Date: Sun, 21 Oct 2007 12:24:32 +0300 (EEST)
Hello, the reason why your code doesn`t execute is because PHP is server-side
language, i.e. it is only processed on the server. Thus when your print PHP
statements via "echo" through your Javascript, which in terms is a client-side
language, i.e. processed on your machine, you actually print pure HTML and
text, and nothing happens. Note that you can do the reverse sometimes, print
javascript via PHP and it will get executed because you pass it to the
client-side. Hope you understood me here. I couldn`t figure out why you choose
to print via javascript when you could simply echo-ed it: <?php
echo'$REMOTE_ADDR';?>.
Now to the second question.
In your solution, you don`t actually upload the file but just read its name and
tmp_name. Use bool move_uploaded_file ( string $filename, string $destination )
to upload the file like this:
<?php
$target_path = 'upload/';
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']) ;
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been
uploaded";
}
else {
echo "Sorry, there was a problem uploading your file.";
}
?>
P.S. I changed the current dir to "upload" dir relative to the uploader.php
file because it didn`t work on my home Windows server with the current
directory.
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