RE: Help with python
- From: "edward" <personal.edward@xxxxxxxxx>
- To: <programmingblind@xxxxxxxxxxxxx>
- Date: Tue, 27 Oct 2009 14:36:29 -0400
Line 3, it states index should be integers not list items.
Edward
-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Richard Dinger
Sent: Tuesday, October 27, 2009 1:48 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: Re: Help with python
What error messages are you getting?
The most obvious error is nothing is indented.
----- Original Message -----
From: "edward" <personal.edward@xxxxxxxxx>
To: <programmingblind@xxxxxxxxxxxxx>
Sent: Tuesday, October 27, 2009 9:58 AM
Subject: RE: Help with python
> Hello,
>
> If you don't mind taking a look at this function. It is supposed to take
> out duplicate entries in a list but its not working for some reason.
>
> Thanks
> Edward
>
> def dup(old_list):
> for item in old_list:
> if old_list[item] not in new_list:
> new_list.apend.item
> return new_list
>
> a=['eggs','bread','soda','bread']
> b=dup(a)
> print b
>
> -----Original Message-----
> From: programmingblind-bounce@xxxxxxxxxxxxx
> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Ken Perry
> Sent: Saturday, October 24, 2009 11:55 PM
> To: programmingblind@xxxxxxxxxxxxx
> Subject: RE: Help with python
>
>
>
> Well the key is your instructor said it doesn't have to be in order. The
> structure I would use is a dictionary. I am not sure there is a cleaner
> way
> to do this but I can tell you adding to a dictionary in python is one very
> fast function so the following is how I would do it. Note the try except
> that is there for the first time you add a word to a dictionary that could
> also be handled by an if statement that checked to see if there was
> already
> key in the list and adding it if there wasn't like I do in the except
> statement but I felt that that would make the code to long.
>
> list=['the','word','the','is','the','mode','of','the','list']
> dict={}
> for u in list:
> try: dict[u]+=1
> except: dict[u]=1
>
> print "The unique list is %s\n" % str(dict.keys())
>
> word=''
> count=0
> for k, v in dict.iteritems():
> if v>count:
> word=k
> count=v
>
>
> print "the string witht he most is %s and there are %d of them\n" %
> (word,count)
>
> -----Original Message-----
> From: programmingblind-bounce@xxxxxxxxxxxxx
> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of edward
> Sent: Saturday, October 24, 2009 6:21 PM
> To: programmingblind@xxxxxxxxxxxxx
> Subject: RE: Help with python
>
> Hello
>
> Thank you for the email.
>
> Yes I think I was reading the problem wrong but I did write the code and
> it
> works fine. Problem two is a problem however.
> edward
>
> -----Original Message-----
> From: programmingblind-bounce@xxxxxxxxxxxxx
> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Martin Slack
> Sent: Saturday, October 24, 2009 5:57 PM
> To: programmingblind@xxxxxxxxxxxxx
> Subject: Re: Help with python
>
> I couldn't remember what a mode was so I looked at:
>
> http://www.mathgoodies.com/lessons/vol8/mode.html
>
> It would seem that both problems have to do with counting the numbers of
> identical elements in a set or list. Can you write a programme to do that
> as a start?
>
> Martin
>
> ----- Original Message -----
> From: "edward" <personal.edward@xxxxxxxxx>
> To: <programmingblind@xxxxxxxxxxxxx>
> Sent: Saturday, October 24, 2009 10:02 PM
> Subject: Help with python
>
>
>> hello all,
>>
>> I have 2 questions on my homework assignment that i cannot figure out.
>>
>> 1. write a function that will return the mode for a data set. A data
>> set is a variable that contains more then one word.
>> 2. Write a function called remove_duplicates that takes a list and
>> returns
>
>> a
>> new list with only the unique elements from the original. Hint: they
>> don't have to be in the same order.
>>
>> any help will be greatly appreciated.
>> Edward
>>
>>
>
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