[geocentrism] Re: More combined post responses
- From: Mike <mboyd@xxxxxxxxxxxx>
- To: geocentrism@xxxxxxxxxxxxx
- Date: Fri, 15 Oct 2004 18:11:53 +0100
Dr. Neville Jones wrote:
> Okay, I think I now follow what you are saying. This contention is
> not really about apparent angular velocity, though, but only of the
> radius of the apparent circle.
Yes, the apparent angular velocity of *every* star is one sidereal day
(except the sun of course).
> In terms of rectangular Cartesian coordinates, where we draw the x-
> and y-axes on a sheet of paper and the z-axis comes out of the paper
> towards you, am I right in saying that, if we consider an object at
> some distance along the x-axis, say, then we will perceive a
> particular apparent motion of that object as we rotate around the
> z-axis, and another if we simply travel along the y-axis?
Yes, although we're really talking about rotation about the x axis as
opposed to movement in the yz plane. If we're going to have z coming up
out of the paper then it may be more instructive to consider an object P
at (x,y,z) = (1,1,100) viewd from the origin. The agle between the
z-axis and the line from (0,0,0) is then
cos-1(100 / ((100^2 + 1^2 + 1^2)^-2)) = 0.810 degrees.
So if you looked straight up the z axis from the origin and spun around
you would see P trace a circle of radius 0.81 degrees about the z axis.
If we now move to (0.01, 0, 0) the angle is
cos-1(100 / ((100^2 + 0.99^2 + 1^2)^-2)) = 0.806 degrees.
So the angular displacement of P from our vertical due to us moving
horizontally by 1/10,000th of the distance from the origin to P is only
0.004 degrees.
In fact the ratio, according to conventional physics, of the distance
between two opposite sides of our orbit and the distance between us and
polaris is
2AU / 390 ly = 2 / 25,000,000 = 1/12,500,000th
So the angular displacement of P from our vertical (the celestial north
pole or CNP) due to us moving nearly laterally to the vertical by 2AUs
(i.e. the parallax) is minute compared to angle it makes with the CNP.
If Polaris is 390ly away as claimed by conventional physics and it makes
an angle of .83 degrees (50' of an arc) to the CNP (directly observable)
then the distance the earth would have to travel to be directly beneath
it thus changing its angle to the CNP by 0.83 degrees would be
sin(0.83) X 390ly = 5.6ly = 354,142AU
Conventional physics claims that the earth is only ever displaced by a
maximum of 2AU in its orbit around the sun.
> This point needs to be clarified before I continue.
Indeed, this is the crux of the matter.
Regards,
Mike.
Other related posts:
