[fgmlug] Re: Bash scripting question
- From: Richard Zimmerman <ke4rit@xxxxxxxxx>
- To: fgmlug@xxxxxxxxxxxxx
- Date: Thu, 26 Aug 2010 16:03:01 -0700 (PDT)
Comments inline...
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Richard "Goose" Zimmerman, ke4rit
Mishawaka, IN
________________________________
From: chuq <chuq00@xxxxxxxxx>
To: fgmlug@xxxxxxxxxxxxx
Sent: Thu, August 26, 2010 3:27:10 PM
Subject: [fgmlug] Bash scripting question
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As I am still new to programming and writing bash scripts I have a question for
you guys to see if you can give me a hand with this..
What I would like to accomplish is this (if any part of this is not do able
that
is fine I can make do with what won't work)
I want to type a command such as ./start
from there I would like for it to run a command (gpsd)
-----------------------
<start>
#!/bin/bash
/location/to/gpsd
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Then have it open another console tab and run a different program (kismet)
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Within <start>
./location/to/kismet
*or*
./location/to/script2
# spawns kismet
----------------------
That is the biggest part of what I want, here is the parts that may get tricky
I would like to have the script stop (ctrl-c is fine) when I stop the second
program (kismet)
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When you exit kismet the original start script will end automatically... Are
you
really wanting to end gpsd instead????
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And then if this is still yet possible have it run a different script (./done)
when both of those are done.
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in ./done use the killall command to kill all instances of gpsd or leave
killall
in ./start
--------------------------------
Any help on this would be appreciated..
I have managed to write a few small scripts that help me out with running the
programs with different variable or arguments in them, but I am stumped on
this.
The one thing that I have not been able to figure out is how to have bash
initialize another console window.
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If you want another console just ./bin/bash
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Thanks very much
Chuq
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Hopes this helps...
Richard
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