Chris, To take Tom's comments a step further, when the data sheet states that VOH is 2.4V with VDD equal to 3.0V and an IOH of -18mA, this infers a maximum p-channel ON resistance of 600mV/18mA or 33-Ohms at that dc operating point. As Tom points out, the output channel resistance is a non-linear function of the voltage across the channel and the current through it. However, with a 10pF load, if you were to assume the RC time constant to be around 330ps, you will at least have a rough idea of what to expect for signal risetime (=2.2*RC) from either simulation or lab measurements. -Bill /************************************ / billw@xxxxxxxxxxx / / / / Advanced Electronic Concepts, LLC / / www.aec-lab.com / ************************************ Tom Dagostino wrote: > Chris > > Voh is a DC parameter as others have pointed out. All it means is the > output, if loaded with a 18 mA load will have at least 2.4 volts. Typically > most drivers we see will really be much stronger than the output current > specification at the 2.4V level. Most will put out more than 2 or 3 times > that amount of current. Look at the pullup table in your model to confirm > that, it will be listed next to 3.0-2.4V or 0.6V. > > The rise or fall times into a capacitive load will be dominated by the RC > time constant of the output impedance of the driver and the load > capacitance. The driver will have a non-linear output impedance in most > cases. > > Since it is a capacitive load and if the output is truly a CMOS pullup then > the output will always get to Vcc or 3.0 Volts in your example if enough RC > time constants have passed. The capacitor will have charged and the output > current is then Zero. > > Tom Dagostino > Teraspeed(R) Labs > 13610 SW Harness Lane > Beaverton, OR 97008 > 503-430-1065 > tom@xxxxxxxxxxxxx > www.teraspeed.com > > Teraspeed Consulting Group LLC > 121 North River Drive > Narragansett, RI 02882 > 401-284-1827 > > -----Original Message----- > From: si-list-bounce@xxxxxxxxxxxxx > [mailto:si-list-bounce@xxxxxxxxxxxxx]On Behalf Of Ray Anderson > Sent: Thursday, March 09, 2006 12:33 PM > To: si-list@xxxxxxxxxxxxx > Cc: Ray Anderson > Subject: [SI-LIST] VOH datasheet question > > > > I'm forwarding the following message to the list for Chris since he is = > experiencing e-mail problems at this time that are preventing the list = > from accepting his postings. > > -Ray > > > --------------------------------------------------- > From: "Chris Chalmers" <cchalmers@xxxxxxxxxxx> > To: <si-list@xxxxxxxxxxxxx> > > Si List, > > > This is a bit of a basic question, I just need a push in the right = > direction. > > In datasheets for a CMOS buffer running from 3V, the VOH min=A0 is = > stated as=20 > 2.4V at -18mA. If you are using this buffer to drive another CMOS input = > with a gate capaci tance of 10pF, for example, how does the current = > -18mA relate to the 2.4V VOH min? > > I mean if you are putting through 10Hz through the buffer and change = > from 0 to 1, the input gate capacitance would be fully charged and won't = > be drawing any current.=A0 It surely won't be sitting at 2.4V. > > So if we put together the situation of a CMOS buffer driving a 10pF = > capacitor at 70MHz over a very short line.=A0 The driver will be looking = > straight in to the capacitor.=A0 If the capacitor is big (100pF) then = > the VOH value will be affected since for a particular value of IOH it = > will take a certain time to charge up the cap.=A0 If the frequency of = > operation is high then it will be discharging before it has fully = > charged.=A0 I can see this.=20 > However from the datasheet this relationship is not obvious if my = > thinking is correct. > > > If I know my load capacitance and have an IBIS model, can I ignore this = > VOH in the datasheet and verify that that the VOH of the chip works by = > using the slow setting of the IBIS model and simulating? > > > Thanks in advance > > > Chris > > ********************************************************************** > Please note: CRLO Displays has been renamed to Forth Dimension Displays = > Limited. > This communication contains information which is confidential and may = > also=20 > be privileged. 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