If you are driving but one side, then you effectively excite BOTH the differential (+v/-v) and the common mode (+v/+v) to get the single-ended (+2v/0) -- Since your excitation is a superposition of the two states (differential, a.k.a., perfectly anti-symmetric voltages and common mode, a.k.a., perfectly symmetric voltages) your responses will also be a superposition of the responses to those two states. If you properly can account for that, then you can properly measure differential with single-ended excitations. Normally you account for such by measuring in such a way as to distinguish the responses directly. You, on the other hand, are distinguishing the responses INDIRECTLY. That is valid, with the caveat that precision errors and noise will combine in the calculated results. But if the raw measurements are sufficiently precise and of high enough S/N, then the calculated results can meet requirements. So, your method is sound. Whether your implemmentation suffices to your needs is hard to say from a distance. Sincerely Kevin ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List technical documents are available at: http://www.si-list.net List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu