Hi all, The below is a java loop, simplified from a larger program I am writing. When I look at it, I think that the loop will run from 0-3, or four times, like saying for(idx=0;idx<a.length;idx++) Yet, when I run the program, I get my entire array printed, plus an exception that I am trying to access a[4], which is of course out of the array bounds. I cannot figure out how that loop can possibly go over 4, though!! I very clearly state that if idx is greater than or equal to a.length, break the loop, yet it still hits 4? It has to be something simple in how Java works, but I have stared at this for over an hour and cannot come up with anything. Changing around the order of the statements does not help, either. In fact, the if...else was not there before, I just added that and the break to see if it would help, but it did not. If you see something wrong, please let me know!! import java.util.*; import java.io.*; public class test{ public static void main(String[] args){ String[] a=new String[4]; String b="my,name,is,alex"; a=b.split(","); int idx=0; while(a[idx]!=null){ if(idx>=a.length){ //idx is out of bounds, so quit loop break; }//if else{ System.out.println(a[idx]); }//else idx++; }//while }//main }//test class -- Have a great day, Alex My email is now: mehgcap@xxxxxxxxx __________ View the list's information and change your settings at //www.freelists.org/list/programmingblind