Re: bits question
- From: "Tyler Littlefield" <tyler@xxxxxxxxxxxxx>
- To: <programmingblind@xxxxxxxxxxxxx>
- Date: Sat, 11 Apr 2009 11:59:41 -0600
awesome, thanks.
I'm playing around with the emulator, and was working on getting background
color set up.
so, I have bits 9-12, so I could do something like:
short i;
i<<8=(char)65;
i|=0xf<<12;
which would set the low nibble of the high byte to 0xf. (I think)...
Thanks,
Tyler Littlefield
Web: tysdomain.com
email: tyler@xxxxxxxxxxxxx
My programs don't have bugs, they're called randomly added features.
----- Original Message -----
From: tribble
To: programmingblind@xxxxxxxxxxxxx
Sent: Saturday, April 11, 2009 11:53 AM
Subject: Re: bits question
Hi Tyler --
Sounds like what you need is shift and bitwise operations on the word.
Suppose wd is the word. To get to the upper 4 bits, shift left and use bitwise
ops as follows:
If 15-12 is the nibble you are using, and if x has the bit pattern you want
in the top nibble,
wd |= (x<<12);
This will set all the bits that are set in x, and leave the other bits as
they were in wd.
To clear bits specified in x, do this:
wd &= ~(x<<12);
To completely clear the nibblein wd , just do
wd &=~(0xF<<12);
HTH -- just play around and it will become easier.
--le
----- Original Message -----
From: Tyler Littlefield
To: programmingblind@xxxxxxxxxxxxx
Sent: Saturday, April 11, 2009 10:54 AM
Subject: bits question
Hello list,
I've got a quick question.
I have a short, (16 bits) and need to set the upper 8 bits.
I have 1-F which I need to use, and I need to set them in nibbles.
so it'd look something like
0x00F1
or what ever I used for the last bit. any ideas on how to do this would be
great.
Thanks,
Tyler Littlefield
Web: tysdomain.com
email: tyler@xxxxxxxxxxxxx
My programs don't have bugs, they're called randomly added features.
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