Need bash script Help
- From: "Donald Marang" <donald.marang@xxxxxxxxx>
- To: <programmingblind@xxxxxxxxxxxxx>
- Date: Sat, 24 Jul 2010 19:31:39 -0400
I hope there is someone here with a little experience with functions in a bash
script. I wrote a function that will append a filename to a list of filenames.
The first argument passed is the name of the variable for a list of filenames.
I fashoned this method based on a bash tutorial on how to return values from a
function. that use this method and the 'eval' statements within the if
statement. Since bash functions can not returna string, passing just the name
seems to be a poor man's way to call by reference. The second argument is a
filename that will be appended to the lisst.
I think everything is in order except the line below:
eval _ResultString="'$1'"
I need _ResultString to contain the actual filenames in the variable name in
the variable whose name is the first argument. For some reason I can not get
this statement correct.
Can anybody know how this assignment statement should look?
Here's the function:
AddFilenameToString() {
# $1 is the variable name of the sttring of filenames
# $2 is the new filename to Add
local _ResultName="$1"
local _ResultString=""
eval _ResultString="'$1'"
echo "variable name = $_ResultName"
echo "value = $_ResultString"
if [[ -z "$_ResultString" ]]; then
echo "create new string"
eval $_ResultName="'$2'"
else
echo "append to string"
eval $_ResultName="'${_ResultString}${IFS}$2'"
fi
}
Don Marang
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