RE: conditional 'order by'
- From: "Mark W. Farnham" <mwf@xxxxxxxx>
- To: <eugene.pipko@xxxxxxxxxxxx>, <oracle-l@xxxxxxxxxxxxx>
- Date: Fri, 19 Dec 2008 13:47:11 -0500
You've got me really confused. Are F, 0, H, 1, and 2 the names of columns?
If so, how many columns that are candidates to order by do you have?
Are you intending to generate queries to execute or did I miss the memo on a
new syntax involving order by?
Regards,
mwf
_____
From: oracle-l-bounce@xxxxxxxxxxxxx [mailto:oracle-l-bounce@xxxxxxxxxxxxx]
On Behalf Of Eugene Pipko
Sent: Friday, December 19, 2008 11:57 AM
To: 'oracle-l@xxxxxxxxxxxxx'
Subject: conditional 'order by'
Hi all,
I have a query that needs to be ordered by based on the second letter of the
code passed in it.
For instance if the code is '9F9Q' then I'd order by 'F' , then by 'H', then
by any other.
If the code is '7H7Q' then I'd order by 'H', then by 'F', then by any other.
I know that I can do it in 2 steps, but is it possible to do in one sql
statement?
Select .
From .
Where ..
If substr(code,2,1)='F' then
Order by decode(code,'F',0,'H',1,2);
Elsif substr(code,2,1)='H' then
Order by decode(code,'H',0,'F',1,2);
End if;
Thanks,
Eugene
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