RE: Slow running Query.
- From: "Juan Carlos Reyes Pacheco" <jreyes@xxxxxxxxxxxxxxxx>
- To: <oracle-l@xxxxxxxxxxxxx>
- Date: Tue, 22 Jun 2004 13:21:24 -0400
Hi Lex, why you say that, could you showme why please
I show you why I say is the same:
SQL> select * from test;
TEST
----------
1
2
Transcurrido: 00:00:00.00
SQL> select count(*) from test where test is null;
COUNT(*)
----------
1
Transcurrido: 00:00:00.00
SQL> select sum(nvl(test,0)) from test;
SUM(NVL(TEST,0))
----------------
3
Transcurrido: 00:00:00.00
SQL> select nvl(sum(test),0) from test;
NVL(SUM(TEST),0)
----------------
3
Transcurrido: 00:00:00.00
-------Original Message-------
From: oracle-l@xxxxxxxxxxxxx
Date: 06/22/04 12:43:39
To: oracle-l@xxxxxxxxxxxxx
Subject: RE: Slow running Query.
Juan,
unfortunately sum(nvl(column,0)) is not equivalent to nvl(sum(column),0)..
Kind regards,
Lex.
---------------------------------------------
visit my website at http://www.naturaljoin.nl
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-----Original Message-----
From: oracle-l-bounce@xxxxxxxxxxxxx
[mailto:oracle-l-bounce@xxxxxxxxxxxxx]On Behalf Of Juan Carlos Reyes
Pacheco
Sent: Tuesday, June 22, 2004 17:15
To: oracle-l@xxxxxxxxxxxxx
Subject: RE: Slow running Query.
Hi, I will do t he following
Try creating function indexes on composed columns you are queryin and tellme
if this improves something
For example you are using as_date in the where column, but you don't have a
index on substr(ca_date,1,4,....
Only to avoid unncesary plsql work
1. instead sum(nvl(column,0)) I'll use nvl(sum(column),0
2. instead of decode use case
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