RE: SQL help
- From: "Ken Naim" <kennaim@xxxxxxxxx>
- To: <Roger.Xu@xxxxxxxxxxx>, "'Oracle-L@Freelists. Org \(E-mail\)'" <oracle-l@xxxxxxxxxxxxx>
- Date: Thu, 24 Aug 2006 15:04:09 -0500
Select * from (Select customer_number, invoicedate, row_number() over
(partition by customer_number, order by invoice_date desc) rn from
order_history) where rn =3. if you have more than 3 invoice per day you need
to add something to the order by so you get the same 3 records each time you
run it, or you need to replace row_number with rank or dense_rank depending
on your exact needs.
Ken Naim
_____
From: oracle-l-bounce@xxxxxxxxxxxxx [mailto:oracle-l-bounce@xxxxxxxxxxxxx]
On Behalf Of Roger Xu
Sent: Thursday, August 24, 2006 2:34 PM
To: Oracle-L@Freelists. Org (E-mail)
Subject: SQL help
SQL> select CUSTOMER_NUMBER,INVOICEDATE
2 from order_history
3 order by CUSTOMER_NUMBER,INVOICEDATE;
CUSTOMER_N INVOICEDA
---------- ---------
1137065 10-AUG-06
1137065 10-AUG-06
1137065 17-AUG-06
1137065 17-AUG-06
1137065 18-AUG-06
1137065 18-AUG-06
1137065 21-AUG-06
1137065 22-AUG-06
1137599 19-AUG-06
1137599 19-AUG-06
1137599 20-AUG-06
1137599 20-AUG-06
1137599 22-AUG-06
1137599 22-AUG-06
1137599 23-AUG-06
1137599 23-AUG-06
16 rows selected.
How do I modify this SQL to find out the last 3 invoiceDATE for each
customer without using PL/SQL?
CUSTOMER_N INVOICEDA
---------- ---------
1137065 18-AUG-06
1137065 21-AUG-06
1137065 22-AUG-06
1137599 22-AUG-06
1137599 23-AUG-06
1137599 23-AUG-06
Thanks,
Roger
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