[ncolug] Re: some bash to shorten
- From: <cstickelman@xxxxxxxxxx>
- To: ncolug@xxxxxxxxxxxxx
- Date: Thu, 3 Dec 2009 2:20:10 -0500
Maybe... I'll check into that...
Chuck
---- nor thern <zboson2003@xxxxxxxxx> wrote:
> thank you , Chuck.
> the outputs are shown below.
> ls -l /proc/kcore | cut -f5 -d" "
> 9663680512
> grep "MemTotal" /proc/meminfo|cut -d ":" -f2|sed '/ kB/ s/ kB//g'|cut -c9-
> 8199584
> free | grep "Mem"
> Mem: 8199584 5968036 2231548 <snipped off last fields>
>
>
> tried to factor the proc/kcore value to see where it came from.
> 2^12 x 61 x 38677
> does /proc/kcore include video ram to make the number larger?
> --- On Sun, 11/29/09, cstickelman@xxxxxxxxxx <cstickelman@xxxxxxxxxx> wrote:
>
> From: cstickelman@xxxxxxxxxx <cstickelman@xxxxxxxxxx>
> Subject: [ncolug] Re: some bash to shorten
> To: ncolug@xxxxxxxxxxxxx
> Cc: "nor thern" <zboson2003@xxxxxxxxx>
> Date: Sunday, November 29, 2009, 9:04 PM
>
> How about:
> ls -l /proc/kcore | cut -f5 -d" "
>
> or
> ls -lh /proc/kcore | cut -f5 -d" "
>
> if you want the results to be human-readable...
>
> Chuck
>
> ---- nor thern <zboson2003@xxxxxxxxx> wrote:
> > grep "MemTotal" /proc/meminfo|cut -d ":" -f2|sed '/ kB/ s/ kB//g'|cut -c9-
> >
> > this is the shortest that i have found to print the RAM size as an integer.
> > unprivileged user .
> > suggestions to shorten this appreciated.
> >
> >
>
>
>
>
>
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