[mso] Re: Project - Any ideas
- From: "Christine" <blue3123@xxxxxxxxxxxx>
- To: <mso@xxxxxxxxxxxxx>
- Date: Tue, 15 Apr 2008 19:52:52 -0700
Thanks, I'm still working through your suggestion. It's not a "homework"
exercise per say, it is something I actually have to do for work.
And to just to clarify on the 200 people, 21 tables, there is an extra table
in case there are unexpected attendees, so what we have to do is spread the
200 people out on the 21 tables, so there will be some tables with 8 or 9
for some meals, but we don't want an empty table or one with one or two
people. Guess I didn't make that clear.
Thanks, I may be back for help.
Christine
-----Original Message-----
From: mso-bounce@xxxxxxxxxxxxx [mailto:mso-bounce@xxxxxxxxxxxxx] On Behalf
Of David Smart
Sent: Monday, April 14, 2008 6:14 AM
To: mso@xxxxxxxxxxxxx
Subject: [mso] Re: Project - Any ideas
Hi
Sorry, probably jumped a bit. We're so used to getting "please do my
homework" questions that I possibly tend to leap to confusions. Enjoy the
exercise. It's not a trivial one. Please feel free to come back with
questions when (if) you get stuck.
Regards, Dave S
----- Original Message -----
From: "Christine" <blue3123@xxxxxxxxxxxx>
To: <mso@xxxxxxxxxxxxx>
Sent: Monday, April 14, 2008 3:47 AM
Subject: [mso] Re: Project - Any ideas
> Thank you for your advise. I wasn't asking for anyone to do it for me, I
> want to do it myself, that's the only way I learn, but I was just lost as
> to
> where to start. I'm going to go through what you said work on it this
> week.
> I really appreciate the advise as it gives me a place to start.
>
> Christine
>
> -----Original Message-----
> From: mso-bounce@xxxxxxxxxxxxx [mailto:mso-bounce@xxxxxxxxxxxxx] On Behalf
> Of David Smart
> Sent: Saturday, April 12, 2008 10:49 PM
> To: mso@xxxxxxxxxxxxx
> Subject: [mso] Re: Project - Any ideas
>
> This definitely looks like a homework exercise. You need to do it - not
> us.
>
> Also, I don't understand your explanation. E.g. 21 tables of 10 people is
> 210 people, not 200. You also don't make it clear exactly what you mean
> by
> the 12 people who will be assigned to the first 12 tables.
>
> You are going to need to break this down. For instance, you can
> presumably
> pre-allocate your 12 people to their specific tables. As such, they are
> not
>
> part of your random allocation. But also, those 12 tables have fewer
> slots
> (9) than the other tables (10). So dispose of these 12 people first.
>
>> Ideally, each person should sit with a different 9 people for each meal.
>
> This really starts to rule out randomness (but I wouldn't be likely to use
> randomising for the allocation patterns in the first place).
>
> I think I would:
>
> - allocate "people-icons" to the tables for the first meal - using a
> definitely non-random allocation scheme.
> - move each "people-icon" clockwise on "increment" for the next meal.
> - do the same for the remaining two meals.
>
> Now a "people-icon" is not a person, it's something you will associate
> with
> a person right at the end. It's probably just a number running from 1 to
> 200 that will eventually be associated with people. Your special 12 will
> be
>
> associated with the numbers 1-12.
>
> An "increment" is a separation factor. Basically it's "(meal number - 1)
> *
> (table position - 1)". This means that the person at the "head" of the
> table (which includes your special 12) is in "table position" 1 and stays
> on
>
> the same table for all the meals. The next person on the table ("table
> position" 2) moves around by one table each time. The next person moves
> by
> 2 tables each time. And so on. So you're splitting them up. (A
> "people-icon" always stays at the same "table position" on whatever table
> it's on.)
>
> So we have your special 12 always at the same tables. Plus another 8 or 9
> (depending on how many tables there actually are) pseudo-special people
> who
> also stay at the same tables, and everyone else is moving by varying
> numbers
>
> of table.
>
> Not random - predictable. And thus able to satisfy the rules easily.
>
> Now for some randomness ...
>
> - Allocate your special people to the first 12 "people-icons", then
> randomly
>
> allocate the other people to the rest.
> - Scramble the seating order within tables away from the "table position"
> order.
> - Scramble the table numbers for tables 13 to 20 (or is it 21) for each
> meal.
>
> The end result will be almost indistinguishable from a true random
> approach.
>
> You will also get a slightly better looking result if you do a semi
> randomisation of the first 12 tables. I.e. keep them together but don't
> put
>
> them in numerical order. This means that people with high "table
> positions"
>
> won't so obviously just be moving the same number of tables each time.
>
> Regards, Dave S
>
>
> ----- Original Message -----
> From: "Christine" <blue3123@xxxxxxxxxxxx>
> To: <mso@xxxxxxxxxxxxx>
> Sent: Sunday, April 13, 2008 3:00 PM
> Subject: [mso] Project - Any ideas
>
>
>> Hi all,
>>
>>
>> I need to generate 200 sets of 4 different random numbers between 1-21.
>> For
>> each position in the set, (ie random number 1, random number 2, etc) each
>> number can only be selected 10 times. At least this is what I think I
>> need
>> to do. I can generate random numbers in Excel, but I don't see a way to
>> generate a set of 4 random numbers.
>>
>>
>>
>> Here's what I'm trying to do.
>>
>>
>>
>> I have to assign 200 people to 21 tables for 4 different meals at an
>> upcoming conference.
>>
>>
>>
>> 200 people
>>
>> 21 tables
>>
>> 10 people per table
>>
>> 4 meals
>>
>> Everyone should sit at a different table for each meal.
>>
>> Except there are 12 people who will be assigned to the first 12 tables
>> for
>> each meal.
>>
>> Ideally, each person should sit with a different 9 people for each meal.
>>
>>
>>
>> So I need to figure out a way to assign each person to a different table
>> for
>> each meal,
>>
>> Make sure it's a different 10 people for each meal
>>
>> and make sure there are no more than 10 people assigned to a single table
>> for each meal and table 1 can only have 7 people randomly assigned to it.
>>
>> There is an extra table in case there are last minute attendees, so it
>> works
>> out that each table will have either 10 or 9 or in a few cases, 8 people
>> per
>> table. That's ok, but I want less than that any table.
>>
>>
>>
>> Anyone have any ideas? I'm better at Excel, but I have MS Access
>> available
>> also.
>>
>>
>>
>> Thanks,
>>
>>
>> Christine
>>
>>
>>
>>
>>
>>
>>
>>
>>
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