[mso] Re: Access 2002: IIf Statement Results Not What's Needed

  • From: Cathy.Evans@xxxxxxxxx
  • To: mso@xxxxxxxxxxxxx
  • Date: Mon, 2 Aug 2004 08:50:58 -0400

Jim, thank you! CID_CV: IIf(CStr([CID]) ="00",[SiteID],[CID]) works great!
Another happy mso/freelist camper!

Regards, Cathy


                                                                                
                                   
                      "Jim Pettit"                                              
                                   
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                      s.org                    Subject:  [mso] Re: Access 2002: 
IIf Statement Results Not What's   
                      07/30/2004 05:12 PM         Needed                        
                                   
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Cathy--

Try this:
CID_CV: IIf([CID] Like "????00*",[SiteID],[CID])

Now, that assumes that the CID field contains at least 6 characters. If I
understand you right, though, your CID field may actually be a calculated
field showing only the 5th and 6th characters of your original 10-11 digit
field. If *that's* the case, the following should work:
CID_CV: IIf([CID] = "00",[SiteID],[CID])

If not, I'm not sure, unless Access is trying to compare against a
numerical
value. If that's happening, you can coerce the CID value into a string:
CID_CV: IIf(CStr([CID]) ="00",[SiteID],[CID])

Let me/us know...

--Jim


----Original Message Follows----
From: Cathy.Evans@xxxxxxxxx
Reply-To: mso@xxxxxxxxxxxxx
To: mso@xxxxxxxxxxxxx
Subject: [mso] Access 2002: IIf Statement Results Not What's Needed
Date: Fri, 30 Jul 2004 14:03:39 -0400

I'm trying to convert a 2 character field based on a value.  My query picks
off positions 5 and 6 of a 10-11 character alpha/numeric string.  Sometimes
the 2 digits are 00, though I'm not sure access is reading them as zero,
since it is alpha/numeric mix and some results are 00, some are
combinations of letters.  I'm trying to convert this 2 character  result to
always use the CID field unless it contains 00, then use the SiteID field.
Here is my formula:

CID_CV: IIf(([CID])="*0*",[SiteID],[CID])

It is not changing the value to SiteID, it is staying 00.  Where am I going
wrong?  Thank you, Cathy






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