Re: newbie question: ffi.sizeof()
- From: Patrick Masotta <masottaus@xxxxxxxxx>
- To: luajit@xxxxxxxxxxxxx
- Date: Wed, 20 Jun 2012 03:27:25 -0700 (PDT)
you are right, the problem is the function (not LUA) that I'm using to print
the numeric value
Thanks guys.
--- On Wed, 6/20/12, Peter Cawley <corsix@xxxxxxxxxx> wrote:
From: Peter Cawley <corsix@xxxxxxxxxx>
Subject: Re: newbie question: ffi.sizeof()
To: luajit@xxxxxxxxxxxxx
Date: Wednesday, June 20, 2012, 3:12 AM
On Wed, Jun 20, 2012 at 11:07 AM, Patrick Masotta <masottaus@xxxxxxxxx> wrote:
I did what you say but I'm getting sz=0, not 50 as expected ... :-(
The C string is there with the correct initial value and all of that..
I just cannot get its size.
what could be wrong?
It seems to give the correct result for me:
E:\CPP\2010\LuaJIT-2.0.0-beta10\bin>luajit.exe
LuaJIT 2.0.0-beta10 -- Copyright (C) 2005-2012 Mike Pall. http://luajit.org/
JIT: ON CMOV SSE2 SSE3 SSE4.1 fold cse dce fwd dse narrow loop abc fuse
> ffi = require"ffi"
> var_01 = ffi.new("char[50]", "initial value for var_01" )
> sz = ffi.sizeof(var_01)
> print(sz)
50
If you're not seeing the correct result, then reduce your code to a minimal
test case like above, and we'll probably be able to identify the problem.
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