Re: luajit string to char * conversion
- From: Florian Weimer <fw@xxxxxxxxxxxxx>
- To: luajit@xxxxxxxxxxxxx
- Date: Sat, 22 Nov 2014 23:44:22 +0100
* marcelo nicolet:
> I catched the trick: when the argument will not be modified, declaring
> it const does the job.
> But when it will be modified (as in my example for recv() ) to have in
> the middle of lua code a call to malloc() and then to free() is not a
> "good thing" to my taste.
At least it's explicit about the lifetime of the temporary copy, and
it doesn't drive the garbage collector forward.
> What about
> local v = ffi.new( "char[?]", bufsize )
> Is it ok?
> TIA
Yes, but you still have to copy the string, and make sure that you
deal with the terminating NUL byte.
> PS: what if malloc() cannot allocate any memory? NULL from malloc
> comes as nil to lua code?
Correct (if malloc does indeed return NULL—usually, the kernel kills
entire processes if it runs out of memory).
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