Re: [BUG?] Segmentation fault in lua_error() - easily reproducible
- From: "Sergei Zhirikov" <dmarc-noreply@xxxxxxxxxxxxx> (Redacted sender "sfzhi@xxxxxxxxx" for DMARC)
- To: "luajit@xxxxxxxxxxxxx" <luajit@xxxxxxxxxxxxx>
- Date: Sun, 14 Dec 2014 09:38:28 +0000 (UTC)
Finally, someone with common sense. Thank you.
Back to the point, which is my original email. Please kindly ignore everything
written after that as irrelevant. However, to avoid any further meaningless
arguments, here is a modified version of the example code, which does not
change anything with respect to the segmentation fault:
#include <lua.h>
#include <lualib.h>
#include <lauxlib.h>
#include <stdio.h>
int main()
{
lua_State *lua = luaL_newstate();
luaL_openlibs(lua);
lua_State *lua2 = lua_newthread(lua);
luaL_loadstring(lua2, "coroutine.yield()");
int res = lua_resume(lua2, 0);
printf("res=%d, top=%d\n", res, lua_gettop(lua2));
lua_pushliteral(lua2, "test");
lua_error(lua2);
return 0;
}
________________________________
From: William Adams <william_a_adams@xxxxxxx>
To: luajit@xxxxxxxxxxxxx
Sent: Sunday, December 14, 2014 6:13 AM
Subject: RE: [BUG?] Segmentation fault in lua_error() - easily reproducible
This argument has devolved into a slapping fight.
Can you please move on, or get back to a point where meaningful help can be
offered.
Sent from my Windows Phone
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