What I mean, of course, is that I was totally thinking the same thing. Yeah. All along. All along I was thinking "What Weil must have in mind is Aristotle's Square of Opposition". Clearly. It's the Square-of-Opposition-thing. Good job JL. High five. We're on the same page. Go team. Erin TO ----- Original Message ----- From: "Erin Holder" <erin.holder@xxxxxxxxxxx> To: <lit-ideas@xxxxxxxxxxxxx> Sent: Friday, August 06, 2004 11:17 PM Subject: [lit-ideas] Re: [lit-ideas] Le Pesanteur et la Grâce > Oh. Sure. Crystal. :) > > > Erin > TO > > ----- Original Message ----- > From: <Jlsperanza@xxxxxxx> > To: <lit-ideas@xxxxxxxxxxxxx> > Sent: Friday, August 06, 2004 11:13 PM > Subject: [lit-ideas] Le Pesanteur et la Grâce > > > > > > In a message dated 8/6/2004 10:38:10 PM Eastern Standard Time, > > erin.holder@xxxxxxxxxxx writes: > > Okay, I made up my own version as to what number one must mean, so I can > > feel like I'm making progress, and now I'm on to number two. > > "The demonstrable correlation of opposites is an image of the > > transcendental > > correlation of contradictories." > > Someone help me here or I won't make it to three. > > ---- P. F. Strawson once said that what can be said nonsensically in one > > language can be said nonsensically in another (cited by Mundle, Critique > of > > Linguistic Philosophy). This may be a case in point? The original: "La > > correlation demonstrable des opposites est an image de la correlation > trascendentale > > des contradictories." --- tr. into English by Arthur Wills. What Weil may > have > > in mind is Aristotle's Square of Opposition? (Affirmo, Nego): > > > > A E > > > > I O > > > > Consider 'red', 'blue', and 'non-blue'. If x is blue, then x is not red. > If > > x is blue, then x is not non-blue. That x is not blue if x is red is a > > _demonstrable_ correlation (it can be demonstrated). What this is an > 'image' of is > > the _trascendental_ (and thus non-demonstrable by 'deductive' logic) > > correlation of 'blue' and 'non-blue'. One minor problem is that for Kant > (and > > Kantians) trascendental correlations are just as demonstrable as your c > > ommon-or-garden 'demonstrable' correlation. In fact, Kant speaks of the > 'trascendental > > deduction'. Perhaps he should mean 'ab-duction', though. Clear? :-) > > Cheers, > > > > JL > > > > > > > > > > > > > > > > ------------------------------------------------------------------ > > To change your Lit-Ideas settings (subscribe/unsub, vacation on/off, > > digest on/off), visit www.andreas.com/faq-lit-ideas.html > > > > > ------------------------------------------------------------------ > To change your Lit-Ideas settings (subscribe/unsub, vacation on/off, > digest on/off), visit www.andreas.com/faq-lit-ideas.html > ------------------------------------------------------------------ To change your Lit-Ideas settings (subscribe/unsub, vacation on/off, digest on/off), visit www.andreas.com/faq-lit-ideas.html