[geocentrism] BA explanation for solar eclipse shadow
- From: "Gary L. Shelton" <GaryLShelton@xxxxxxxxxxx>
- To: <geocentrism@xxxxxxxxxxxxx>
- Date: Wed, 13 Oct 2004 23:44:00 -0500
Group,
This is one of two solid responses I received from BA as to why the solar
eclipse does not prove geocentrism, but rather works as predicted. The other
one involves an attachment but basically says the same thing as this one.
This is what the other side says....
Gary
-----------
Gary, I suggest that you read that whole thread because your queries are
answered therein by ToSeek (the thread also includes some masterly work by
milli360 - now A Thousand Pardons - where he found errors buried deep in Dr
Jones' code). Part of my humble contribution to that thread included the
following that may be of some help to you in understanding the matter:
Quote:
In the Earth/Moon/Sun situation, regard the Earth & Sun as fixed in
relative position. For the moon's shadow to fall on the Earth, the 'tube of
light' that the moon must traverse is ~2 degrees. To travel 2 degrees in its
orbit takes the moon ~3.5 hours, and so the shadow will cover the diameter of
the Earth in roughly that time. However, it takes Joe Citizen standing on the
surface of the Earth 12 hours to make the same 'journey'. Both shadow and Joe
are moving from West to East, but the shadow is faster and so will outstrip Joe
from the West to East.
But how does Joe see the moon itself? In the 12 hours that Joe can see
the moon he is moving from West to East through 180 degrees. However, the moon
in this time has only moved from West to East through ~7 degrees. The moon will
therefore appear to be moving from East to West from Joe's perspective.
So this model predicts that the moon will traverse the sky from East to
West, but during an eclipse, it's shadow will go from West to East. Which, of
course, is just what we see.
The reason for this is that the position/motion of the moon in the sky from the
perspective of the Earth depends on the respective angular velocities of the
Earth & Moon.....whereas the position/motion of the moon's shadow on the
surface of the Earth depends almost entirely on the moon's tangential velocity.
GaryLShelton@xxxxxxxxxxx
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