> Compression of 2:1 would make the signal half as loud. Ack, did I say that? Oops. That's not right! What I meant to say was, compression of 2:1 would make the signal *over the threshold* half as loud. Hmmm. It might be easier to show you a few examples. Say my threshold is -10db. A signal comes in at -8db, ie, 2db over my threshold. 2:1 compression would reduce this difference by two - so the outgoing signal would be -9db. If I was applying 4:1 compression, then only one quarter of the difference would remain - so instead of being 2db over it would leave being just 0.5db over - ie, a level of -9.5db. Pop quiz: My compressor is set to 6:1 compression with a threshold of -15db, and it just received an incoming signal at 6db. What level will the compressor output? Finally, this should now show you why a compressor with "infinite" compression is the same as a limiter. If you reduce the overflow to (1/infinity) of the value it was before, you've basically taken the difference away completely, so the outgoing signal will be at the threshold level. Hopefully that's the only mistake I made ;) Take care, G. PS: The pop quiz answer is as follows. The difference between the threshold and the signal is 9db. 9db divided by the ratio (6) is 1.5db, so the outgoing signal would be (threshold + 1.5db), which is -13.5db. How did you do?