[wdmaudiodev] Re: Simple MME Question if I may
- From: "phil" <phil@xxxxxxxxxxxxxxxxxxxx>
- To: <wdmaudiodev@xxxxxxxxxxxxx>
- Date: Thu, 13 Mar 2003 15:48:42 -0800
I naively just assumed the preparefunctions would work.. makes it so easy.
And fast. Since the buffers are dealt with immediately. I have not had any
problems with playing... just waveOutReset. Sure wish we had the source code
for those routines. I would really like to know what they are doing. Even
after looking at the list of funcs you are allowed to call more than a few
times.. it just went right past me.!
thanks for your response. i appreciate it very much.
p
----- Original Message -----
From: "Jeff Pages" <jeff@xxxxxxxxxxxxxxxx>
To: <wdmaudiodev@xxxxxxxxxxxxx>
Sent: Thursday, March 13, 2003 2:02 PM
Subject: [wdmaudiodev] Re: Simple MME Question if I may
>
> I suggest you read very carefully the documentation on the wave callback
> functions. You must not call any other wave functions (such as
> waveOutUnprepareHeader) or any but a select few Win32 functions from
within
> these callbacks.
>
> I have found it easier to use the window messages (MM_WOM_DONE, etc)
rather
> than the callback functions, as there are no restrictions on what can be
> called from within the window message loop.
>
> Jeff
>
> ----- Original Message -----
> From: "phil" <phil@xxxxxxxxxxxxxxxxxxxx>
> To: <wdmaudiodev@xxxxxxxxxxxxx>
> Sent: Thursday, March 13, 2003 7:33 AM
> Subject: [wdmaudiodev] Simple MME Question if I may
>
>
> >
> > Hello
> >
> > I am new to this list in the hopes I may find a solution. I am
writing
> > some code to use MME waveaudio calls.. it is a multi-buffer setup and it
> > plays just fine. I am using a callback function to unprepare, prepare
amd
> > write new buffers. However, when I call waveOutReset(hWave) , the first
> > time it goes to the callback function after the call to waveoutReset()
my
> > code hangs inside the call to waveOutUnPrepareheader(); all of the data
in
> > the header seems fine on the call to unprepare the header. dwFlags is a
3
> > which means the buffer is PREPARED and DONE.
> > \
> > Any help would be great! I have not seen this yet and I am a little
> > unsure as to how to deal with it.
> > [phil]
> >
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>
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