[SI-LIST] Re: Why Termination at Both End ?
- From: steve weir <weirsi@xxxxxxxxxx>
- To: Rohit MISHRA <rohit.mishra@xxxxxx>
- Date: Wed, 10 Aug 2011 10:40:26 -0700
Transmission lines do not emulate bandpass/bandstop filters. The
concept of percentage bandwidth is not applicable.
Steve.
On 8/10/2011 6:44 AM, Rohit MISHRA wrote:
> Steve,
>
> I would appreciate if you can explain that why you think that distributed ckt
> doesn't have more bandwidth than lumped ckt ?
>
> Rgds,
> Rohit
>
>
> -----Original Message-----
> From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On
> Behalf Of steve weir
> Sent: Wednesday, August 10, 2011 2:13 PM
> To: si-list@xxxxxxxxxxxxx
> Subject: [SI-LIST] Re: Why Termination at Both End ?
>
>
> On 8/10/2011 12:13 AM, Rajan Hansa wrote:
>> Thanks everyone for clearing my doubt !!
>> I have one more question, I know it may look silly and is very basic but I
>> am sure experts here can enlighten me. Can anyone explain that why it's
>> said that transmission line can be modeled as distributed RLGC model ?
> Because with a sufficient number of sections the model accuracy is
> sufficient to reliably predict Tx line behavior.
>
>> Ok I
>> know distributed model has high bandwidth but why distributed ckt has more
>> bandwidth than lumped ckt ?
> It doesn't.
>
>> Why minimum 10 LC sections are needed for
>> transmission line ?
> That's not correct.
>>
>> Rajan
>>
> Many excellent texts and web references are available for you to learn
> about transmission lines.
>> On Tue, Aug 9, 2011 at 3:55 PM, Rohit MISHRA<rohit.mishra@xxxxxx> wrote:
>>
>>> Rajan,
>>>
>>> Here's my 2 cents :
>>>
>>> I believe you can use a receiver without matching it's input impedance with
>>> transmission line impedance But Only If the system satisfies these
>>> conditions :
>>>
>>> 1) Transmitter is connected to single receiver.
>>> 2) Transmission line is a controlled impedance line and has no
>>> unintentional impedance discontinuities(like via, stub, package lead, etc)
>>>
>>> In real system even though board is designed with controlled-impedance
>>> traces, there is still the opportunity for a signal to see an unintentional
>>> impedance discontinuity and in this case just source termination won't stop
>>> the ringing that's why termination at both end.
>>>
>>> Rohit
>>>
>>>
>>>
>>> -----Original Message-----
>>> From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx]
>>> On Behalf Of Rajan Hansa
>>> Sent: Tuesday, August 09, 2011 1:57 PM
>>> To: si-list@xxxxxxxxxxxxx
>>> Subject: [SI-LIST] Why Termination at Both End ?
>>>
>>> Experts,
>>>
>>> Can anyone explain that why in some designs we see source as well as load
>>> terminations, I mean termination at both side of traces ? If ringing is a
>>> issue then only source termination should be sufficient to control it and
>>> we
>>> can use a receiver with very high input impedance i.e. no need to match
>>> input impedance of receiver with transmission line characteristics
>>> impedance.
>>>
>>> Rajan
>>>
>>>
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>
--
Steve Weir
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