[SI-LIST] The crosstalk of transmission line when it is completely matched

  • From: Zhangkun <zhang_kun@xxxxxxxxxx>
  • To: si-list <si-list@xxxxxxxxxxxxx>
  • Date: Fri, 06 Dec 2002 11:21:50 +0800

Hi all:

This morning, I do some crosstalk simulation. I find something interesting. The 
following is what I do.

1. Create diffline.rlgc from rlgc.sp
2. Calculate the Z_diff and Z_comm from diffline.rlgc
3. Match the diffline and simulate it by match_2.sp

I find the near end crosstalk and the far end crosstalk are equal. This is not 
same to the general crosstalk theory. I want to know why.

rlgc.sp
.OPTION PROBE POST
VIMPULSE in1 gnd PULSE 0v 5v 5n 2n 2n 20n
W1 in1 in2 gnd out1 out2 gnd FSmodel=cond2_sys N=2 l=1000mil
Rin2 in2 gnd 49
Rout1 out1 gnd 49
Rout2 out2 gnd 49
.MATERIAL diel DIELECTRIC ER=4.5
.SHAPE rect RECTANGLE WIDTH=7mil, HEIGHT=2mil,
.LAYERSTACK stack1,
+LAYER=(PEC,20mil), LAYER=(diel,22mil),
+LAYER=(PEC,20mil)
.FSOPTIONS opt1 PRINTDATA=YES
.MODEL cond2_sys W MODELTYPE=FieldSolver,
+LAYERSTACK=stack1, FSOPTIONS=opt1
+RLGCFILE=diffline.rlgc
+CONDUCTOR=(SHAPE=rect, ORIGIN=(0,30mil)),
+CONDUCTOR=(SHAPE=rect, ORIGIN=(14mil,30mil))
.TRAN 0.5n 100n
.PROBE v(out1)
.END

diffline.sp
*SYSTEM_NAME : cond2_sys
*
*  ------------------------------------ Z = 0.0015748
*  //// Top Ground Plane //////////////
*  ------------------------------------ Z = 0.0010668
*       diel   H = 0.0005588
*  ------------------------------------ Z = 0.000508
*  //// Bottom Ground Plane ///////////
*  ------------------------------------ Z = 0

* N (number of signal conductors)
*********************************
2

* Lo (H/m)
*********************************
3.42622e-07 
6.40120e-08 3.42622e-07 


* Co (F/m)
*********************************
1.50678e-10 
-2.82540e-11 1.50678e-10 


* Ro (Ohms/m)
*********************************
0.00000e+00 
0.00000e+00 0.00000e+00 


* Go (S/m)
*********************************
0.00000e+00 
-0.00000e+00 0.00000e+00 

match_2.sp
the simple diff transmissionline

.options list node post
.op
.tran 0.5n 100n

*driver
vp in1 gnd pulse 0 5 1n 1n 1n 3n 8n
*vn in2 gnd pulse 10 0 1n 1n 1n 3n 8n
rin2 in2 gnd 47.69

*transmission line
Wcable in1 in2 gnd out1 out2 gnd RLGCfile=diffline.rlgc n=2 l=5000mil

*receiver
rout1 out1 node1 39.4598
rout2 out2 node1 39.4598
rcon  node1 gnd 9.0864

.end

Z_diff=78.9195 Z_comm=28.8163
rou1=rout2=Z_diff/2
rcon=(2*Z_comm-Z_diff/2)/2

Best Regards
Zhangkun
2002.12.06


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  • » [SI-LIST] The crosstalk of transmission line when it is completely matched