[SI-LIST] Re: TDR S-parameter and correlation
- From: <dmitry.a.smolyansky@xxxxxxxxxxxxxx>
- To: <Aubrey_Sparkman@xxxxxxxx>, <zhenggang.cheng@xxxxxxxxx>, <si-list@xxxxxxxxxxxxx>
- Date: Thu, 30 Aug 2007 16:23:05 -0700
True enough.
Thanks,
=20
Dima Smolyansky
EOPL Marketing
M/S 39-111
503-627-7180
-----Original Message-----
From: Aubrey_Sparkman@xxxxxxxx [mailto:Aubrey_Sparkman@xxxxxxxx]=20
Sent: Thursday, August 30, 2007 4:09 PM
To: Smolyansky, Dmitry A; zhenggang.cheng@xxxxxxxxx;
si-list@xxxxxxxxxxxxx
Subject: RE: [SI-LIST] Re: TDR S-parameter and correlation
Dima,
"a priori" That's exactly my point. If you don't already know the
answer, you can't determine the exact topology with either instrument.
Not that it really matters; the circuit connected to the ports won't
care whether you have the exact topology or an equivalent topology.=20
Aubrey Sparkman=20
Enterprise Engineering Signal Integrity Team
Dell, Inc.=20
Aubrey_Sparkman@xxxxxxxx=20
(512) 723-3592
"The ultimate measure of a man is not where he stands in moments of
comfort and convenience, but where he stands at times of challenge and
controversy." - Martin Luther King, Jr.
-----Original Message-----
From: dmitry.a.smolyansky@xxxxxxxxxxxxxx
[mailto:dmitry.a.smolyansky@xxxxxxxxxxxxxx]=20
Sent: Thursday, August 30, 2007 5:52 PM
To: Sparkman, Aubrey; zhenggang.cheng@xxxxxxxxx; si-list@xxxxxxxxxxxxx
Subject: RE: [SI-LIST] Re: TDR S-parameter and correlation
Aubrey,
I would think the answer is unambiguous yes, if you do not have splits
and stubs. And you do have splits and stubs, the answer is also yes, but
qualified with "if you know enough about your topology a priori."
Thanks,
=20
Dima Smolyansky
Tektronix, Inc.
P.O. Box 500, MS 39-111
Beaverton, OR 97077-0001
503-627-7180
503-627-2260 (fax)
-----Original Message-----
From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx]
On Behalf Of Aubrey_Sparkman@xxxxxxxx
Sent: Thursday, August 30, 2007 1:06 PM
To: zhenggang.cheng@xxxxxxxxx; si-list@xxxxxxxxxxxxx
Subject: [SI-LIST] Re: TDR S-parameter and correlation
Here's a thought: Even if you use a TDR, do you really think you can
tell exactly what the topology is, if it's in a box and you can't see
it?=3D20
Aubrey Sparkman=3D20
Enterprise Engineering Signal Integrity Team Dell, Inc.=3D20
Aubrey_Sparkman@xxxxxxxx=3D20
(512) 723-3592
"The ultimate measure of a man is not where he stands in moments of
comfort and convenience, but where he stands at times of challenge and
controversy." - Martin Luther King, Jr.
-----Original Message-----
From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx]
On Behalf Of ZHENGGANG CHENG
Sent: Thursday, August 30, 2007 2:30 PM
To: si-list
Subject: [SI-LIST] TDR S-parameter and correlation
Hi,
My question is:
If we TDR (assuming the TDR method is 100% correct) the equivalent
circuit converted using S-parameter, will the result is exactly the same
as real TDR of the same DUT? (assume the converting error and bandwidth
are not issues) Assume this DUT has many large discontinuities inside.
To me, the real TDR can distinguish all the discontinuities inside a
DUT; however, the S-parameter is only the characterization at the ports
rather than inside. Will two equivalent circuits give the same
S-parameter but have two different topologies?
Look froward to your replies.
Thanks,
ZG
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