[SI-LIST] Re: Scope probe attenuation
- From: "Degerstrom, Michael J." <degerstrom.michael@xxxxxxxx>
- To: Aklein@xxxxxxxxxxxxxxxxxxxxxxxxxx, si-list@xxxxxxxxxxxxx
- Date: Fri, 3 Aug 2001 08:38:21 -0500
Adam,
Assuming that the scope's impedance is 50 ohms then your
attenuation is simply a voltage divider, i.e.,
attenuation=(50/(1K+50)). That's why a 10X probe will
use a 450 ohm resistor in the probe since 50/(450+50) = 1/10.
Mike
_______________________________________________________________
Mike Degerstrom Email: degerstrom.michael@xxxxxxxx
Mayo Clinic; 200 1st Street SW ; Rochester, MN 55905
Phone: (507) 538-5462 FAX: (507) 284-9171
WWW: http://www.mayo.edu/sppdg/sppdg_home_page.html
_______________________________________________________________
> -----Original Message-----
> From: Adam Klein [mailto:Aklein@xxxxxxxxxxxxxxxxxxxxxxxxxx]
> Sent: Thursday, August 02, 2001 2:31 PM
> To: SI
> Subject: [SI-LIST] Scope probe attenuation
>
>
>
> Hello,
>
> My question is regarding scope probe attenuation.
>
> I have a Tektronix TDS640A oscilloscope which has four
> channels designed
> for either 50 Ohm or 1M Ohm probes I have a 1K Ohm probe
> which works as far
> as displaying a wave form but the amplitude is considerably
> less than it
> should be. Does anybody know an equation that I can apply to
> find out the
> exact difference in attenuation between this probe and a 50
> Ohm probe your
> help is appreciated.
>
>
> Adam
>
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