[SI-LIST] Re: SSTL termination resistor power
- From: Bi Han <mike_bihan@xxxxxxxxxxxx>
- To: George Tang <gtang@xxxxxxxx>, List` Si <si-list@xxxxxxxxxxxxx>
- Date: Fri, 26 Aug 2005 09:04:33 -0700 (PDT)
Tang:
Thanks for the information.
One major problem with it, is the different termination impedance for DC-AC
range. If the data is not well coded, like 8B/10B, then could cause problem.
Thanks again for the inputs.
Han
George Tang <gtang@xxxxxxxx> wrote:
Han,
I have not worked on DDR memory design for over 5 yrs, and I don't remember
what we did before, so don't take my word for it. However, here is
something to think about.
Do an AC 60 ohm termination to gnd with a 1k pullup and 1k pulldown for the
DC voltage bias.
^
|
1K
Driver -->-----------------|
| |
Z |
| 1K
= |
| |
V V
George
-----Original Message-----
From: si-list-bounce@xxxxxxxxxxxxx
[mailto:si-list-bounce@xxxxxxxxxxxxx]On Behalf Of Bi Han
Sent: Thursday, August 25, 2005 8:17 AM
To: List` Si
Subject: [SI-LIST] SSTL termination resistor power
SSTL termination might use ODT termination for receiver side.
The implementation is about 120ohm between PAD and VDDQ, another 120ohm
between PAD and VSSQ. Overall AC impedance is about 60ohm.
Since signal is DC coupled, there is DC current burning in terminaion
resistors. If the PCB trace impedance is 60ohm, then the DC current in the
termination resistor is about 20mA. It is so huge that I can not believe
that DDR memory can afford it.
Is there any way to reduce the power?
thanks,
Han
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