[SI-LIST] Re: SDRAM timing

  • From: "Christopher R. Johnson" <crjohnson11@xxxxxxxxxxx>
  • To: <peter.zhu@xxxxxxxxxx>
  • Date: Mon, 29 Nov 2004 10:20:24 -0500

If you have zero skew (all lines the same length), then there is some
optimum point at which you can place your clock to give the best setup and
hold for all signals.  Once you introduce skew between any of the signals,
from trace length, different output prop delays, different receiver
thresholds, clock jitter, etc. you no longer have a single point in the
cycle which is best for all signals.  Your best point is now fuzzed out to a
band of different best points across all of the signals.  The best you can
do is minimize the difference between the individual best clock placements
and the actual clock placement.  To do this, you place your clock midway
between the best placement for slowest and fastest signals.  The point at
which the "fuzzed out" clock placement equals the system clock is the
fastest that you can go.


----- Original Message ----- 
From: "peter zhu" <peter.zhu@xxxxxxxxxx>
To: <bmgman@xxxxxxxxxx>
Cc: <si-list@xxxxxxxxxxxxx>
Sent: Monday, November 29, 2004 7:26 AM
Subject: [SI-LIST] Re: SDRAM timing


> Mike and all:
>
> I think the setup and hold time is not a problem in shortest data bus.
> Assume that the length of data bus is ZERO, because no any data bus delay,
> so the timing will be just the timing in SDRAM or SDRAM controller
> datasheet!!! It's perfect!
> So I think the shorter, the better.
> Can anybody explain it? Do we really need to maintain the almost same
length
> in SDRAM data bus?
>
> Thanks in advanced.
>
> Peter


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