[SI-LIST] Re: Return Path
- From: Darshan Mehta <darshanmehta2k@xxxxxxxxx>
- To: steve weir <weirsi@xxxxxxxxxx>, si-list@xxxxxxxxxxxxx
- Date: Thu, 4 Aug 2005 23:04:48 -0700 (PDT)
Steve,
Thanks for the reply.
So you mean to say that if we don?t have Plane Layer, the Electric and Magnetic
field will be coupled to the nearby conductor. If we have a Plane layer also
present on the board, does the nearby conductor act as a Return path? My basic
question is, on what basis we should think that this conductor will act as a
return path for given signal. If the Plane shape is present on the board, does
the Plane as well as the nearby conductors will act as a return current or only
the Plane shape will act like return current path.
Thanks,
Darshan Mehta
steve weir <weirsi@xxxxxxxxxx> wrote:
Darshan, if you have a board with no dedicated plane, then the fields will
just spread out, coupling the signal into multiple conductors. A field
solver can determine the coupling on each line for a given configuration.
Steve.
At 10:31 PM 8/4/2005 -0700, Darshan Mehta wrote:
>Hello Experts,
>
>
>
>I have a question on return current. I was going through the book "Signal
>Integrity Simplified" and came to know that return current path can be a
>Power Plane or Ground Plane. I am still confused about return path. Let me
>describe what I understood.
>
>
>
>The Signal Path is the active path and the Electric field from Signal will
>terminate in the return path. The Magnetic field will form a circular loop
>around the signal and it will be coupled with return path so that equal
>and opposite current will flow in return path. Normally if we have Power
>Plane or Ground place, the return path will be easy to find out. Let's
>assume, if we have a 2 layer board with no copper shape drawn on it, how
>to find the return path for the signal? Please help me understanding this.
>
>
>
>Thanks,
>
>Darshan Mehta
>
>
>
>
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